Question

In this problem, we will follow the transmission of four genes, namely A, B, C and D. Each gene has a dominant and a recessive allele.

Cross: Aa Bb Cc Dd x Aa bb Cc Dd

The probability of producing a child which phenotypically resembles either one of the two parents is _____

Answer 1

The probability of producing a child which phenotypically resembles either one of the two parents is 1/16 or 0.0625, which is 6.25%.

Step-by-step explanation:

The probability of producing a child which phenotypically resembles either one of the two parents can be calculated using the laws of chance and probability. In this cross, AaBbCcDd x AabbCcDd, we are interested in the phenotypic resemblance with either one of the two parents. To calculate the probability, we need to consider the probability of inheriting the dominant alleles at each gene locus. In this case, there are four gene loci, so the probability can be calculated by multiplying the probabilities at each locus.

For each gene locus, there are two possible alleles, one dominant and one recessive. In this cross, the probability of inheriting a dominant allele at each locus is 1/2, since both parents are heterozygous. Therefore, the probability of producing a child with a phenotype resembling either one of the two parents is (1/2)^4, which is equal to 1/16 or 0.0625. So, the probability is 0.0625 or 6.25%.