Question

How much woek is done by the wind as the bug undergoes displacement Δr=(7.5 i−7.5j)m ? Express your answer with the appropriate units. A 45 \& bug s hovering in the ar A gusi of wind exerts a force F=(4.0i−6.0j)×10 N−² on the bug * Incorrect;

Answer 1

The work done by the wind on the bug as it undergoes the given displacement is 75 joules, which is calculated using the dot product of the force vector and the displacement vector.

Step-by-step explanation:

To calculate the work done by the wind on the bug as it undergoes a displacement Δr=(7.5 i−7.5j) meters, we must use the definition of work done by a force. The work W is given by the dot product of the force vector and the displacement vector:

W = F · Δr = FxΔx + FyΔy

In this case, the force exerted by the wind is F=(4.0i−6.0j)×10 N.

Thus, the work done by the wind is:

W = (4.0×10)(7.5) + (−6.0×10)(−7.5)

W = 30 + 45

W = 75 joules

This means that the wind does 75 joules of work on the bug during the displacement.