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A 25 cm spring with spring constant 225 N/m is suspended and an unknown mass is attached to the end of the spring and released so that it oscillates up and down, completing exactly 10 cycles in 3.50 s. What is the mass?

User Chessdork
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Final answer:

The mass attached to the spring in simple harmonic motion is approximately 0.445 kg, calculated using the formula for the period of a spring-mass system.

Step-by-step explanation:

To determine the unknown mass on the spring in a simple harmonic motion, we use the formula T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. Given that the spring completes 10 cycles in 3.50 seconds, the period (T) is 3.50 s / 10 = 0.35 s. The spring constant (k) is given as 225 N/m. Rearranging the formula to solve for mass (m), we get m = kT² / (4π²).

Plugging in the values, we have m = (225 N/m × (0.35 s)²) / (4π²) ≈ 0.445 kg. Therefore, the mass attached to the spring that results in a simple harmonic motion with the given period is approximately 0.445 kg.

User Morklympious
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