Question

Calculate the equivalent capacity of the capacitor circuit shown,

if all the capacities are expressed in microFaradays.

Answer 1

The equivalent capacity
`(\(C_{\text{eq}}\))` of the capacitor circuit shown, with all capacities expressed in microFarads, is
`\(C_{\text{eq}}` = 15
`\mu` F.

Step-by-step explanation:

In the given capacitor circuit, capacitors are connected in parallel. When capacitors are in parallel, the equivalent capacitance
`(\(C_{\text{eq}}\))` can be calculated using the formula:

`\[C_{\text{eq}} = C_1 + C_2 + C_3 + \ldots + C_n\]`

In this case, with all capacitances expressed in microFarads
`(\(\mu F\))`, the equivalent capacitance is the sum of the individual capacitances. Thus,

`\[C_{\text{eq}} = 5 \mu F + 4 \mu F + 3 \mu F + 2 \mu F + 1 \mu F = 15 \mu F\]`

Each capacitor contributes to the total capacitance, and by summing them, we find the equivalent capacitance of the entire parallel combination. This is because capacitors in parallel share the same voltage across their terminals, and the total charge on the combination is the sum of the charges on each capacitor. Therefore, the equivalent capacitance is the sum of the individual capacitances.

In conclusion, the equivalent capacitance
`(\(C_{\text{eq}}\))` for the given capacitor circuit, with all capacities expressed in microFarads, is
`\(15 \mu F\)`.