Final answer:
The orbital period of Venus can be calculated using Newton's version of Kepler's third law, which relates the square of the orbital period to the cubic of the mean orbital radius. By plugging in the given values of the mean orbital radius of Venus and the mass of the Sun into the equation, we can find the orbital period of Venus to be approximately 2.37x10^6 seconds or 0.0749 years.
Step-by-step explanation:
To calculate the orbital period of Venus, we can use Newton's version of Kepler's third law, which states that the square of the orbital period is proportional to the cube of the mean orbital radius. In this case, the mean orbital radius of Venus is given as 1.076x10^11 m. The mass of the Sun is given as 1.99x10^30 kg.
Using the equation P^2 = (4π^2/G) * (a^3/M), where P is the orbital period, a is the orbital radius, G is the gravitational constant, and M is the mass of the Sun, we can calculate the orbital period of Venus.
Plugging in the values, we get P^2 = (4π^2/G) * (1.076x10^11)^3 / (1.99x10^30). Solving for P, we find that the orbital period of Venus is approximately 2.37x10^6 seconds or 0.0749 years.