32.1k views
0 votes
The cart B rotates such that its angular velocity increases according to the equation b = - 1,

where t is expressed in seconds. The cart starts at an angle theta. The sample between the
center and the cart is 5 m. Due to safety reasons, the total acceleration of the
cart should not exceed 10 m/s². At what time does the cart reach this acceleration?

User Jim Todd
by
7.1k points

1 Answer

7 votes

Final answer:

To determine the time at which the cart reaches an acceleration of 10 m/s², we can use the equation for total acceleration and the given equation for the angular velocity. By substituting the value of t into the equation, we can solve for the angular velocity. We can then use this angular velocity to solve for t when the acceleration reaches 10 m/s².

Step-by-step explanation:

Given the equation b = -1, we can determine the angular velocity, in radians per second, at any time t by substituting the value of t into the equation.

To find the time at which the cart reaches an acceleration of 10 m/s², we need to determine the angular velocity at that time and then solve for t.

Since the total acceleration (a_total) is the sum of the tangential acceleration (a_t) and the centripetal acceleration (a_c), we can write:

a_total = a_t + a_c

Since the centripetal acceleration is given by the equation a_c = r * (angular velocity)^2, we can substitute the value of a_c and rearrange the equation to find the angular velocity at the time when a_total reaches 10 m/s².

Once we have the angular velocity, we can substitute it into the equation b = -1 and solve for t.

Therefore, the cart reaches an acceleration of 10 m/s² at the time t when b = -1.

User Yunus Kulyyev
by
8.0k points