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A 192.49g ball attached to a spring with spring constant 10.31

N/m oscillates horizontally on a frictionless table. Its velocity
is 21.46 cm/s when x = -14.60 cm. What is the speed of the ball?

User JakeB
by
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1 Answer

5 votes

Final answer:

The speed of the ball can be determined using the equation v = ω√(A² - x²), where v is the velocity, ω is the angular frequency, A is the amplitude, and x is the displacement. By substituting the given values into the equation, we find that the speed of the ball is approximately 3.25 m/s.

Step-by-step explanation:

The speed of the ball can be determined using the equation:

v = ω√(A² - x²)

where v is the velocity, ω is the angular frequency, A is the amplitude, and x is the displacement.

Given that the ball's velocity is 21.46 cm/s and its displacement is -14.60 cm, we can substitute these values into the equation to solve for the speed.

v = ω√(A² - x²)

21.46 = ω√((0.2146)² - (-0.146)²)

21.46 = ω√(0.0462 - 0.0213)

21.46 = ω√0.0249

ω = 21.46 / √0.0249

ω ≈ 15.16

The speed of the ball is equal to the product of the angular frequency and the amplitude:

Speed = ω * A

Speed = 15.16 * 0.2146

Speed ≈ 3.25 m/s

User TvCa
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