Question

A square, 44.0- turn coil that is 11.0 cm on a side with a resistance of 0.630Ω is placed between the poles of a large electromagnet. The electromagnet produces a constant, uniform magnetic field of 0.500 T directed into the screen. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 2.80 cm/s.

What is the current 1 through the wire coil before the coil reaches the right edge of the field? Define counterclockwise current as positive and clockwise current as negative.

Answer 1

The current induced in the wire coil can be calculated using Faraday's law of electromagnetic induction. The induced current is equal to the rate of change of magnetic flux through the coil.

Step-by-step explanation:

The current induced in the wire coil can be calculated using Faraday's law of electromagnetic induction. According to Faraday's law, the induced current is equal to the rate of change of magnetic flux through the coil. The magnetic flux through the coil is given by the product of the magnetic field and the area of the coil. Since the coil is moving at a constant velocity and the magnetic field is constant, the induced emf and current will remain constant.

The induced emf can be calculated using the formula:

emf = -N * A * (dB/dt)

Where N is the number of turns of wire in the coil, A is the area of the coil, and (dB/dt) is the rate of change of magnetic field. In this case, the magnetic field is decreasing at a rate of 0.500 T/s and the area of the coil is (11.0 cm)^2. Plugging these values into the formula, we can calculate the emf. The induced current can be calculated using Ohm's law: I = emf/R. Substituting the emf and resistance values, we can calculate the current through the coil.