Final Answer:
The initial current flowing through the circuit composed of a 535-Ω resistor, an uncharged 1.50-μF capacitor, and a 6.22 V battery connected in series can be calculated using the formula for the current in a simple series circuit, which is given by Ohm's law combined with the equation governing the charging of a capacitor in a DC circuit. The initial current (I) can be calculated as I = E / R, where E is the emf of the battery and R is the total resistance in the circuit.
Step-by-step explanation:
In a series circuit, the total resistance (R_total) is the sum of individual resistances. Given a 535-Ω resistor, the total resistance is simply the resistance of the resistor, as capacitors initially behave as an open circuit in DC circuits. Therefore, R_total = 535 Ω.
Using Ohm's law (V = I * R) and the given emf of the battery (E = 6.22 V), we can determine the initial current (I) flowing through the circuit. Applying Ohm's law in a series circuit, I = E / R_total. Plugging in the values, I = 6.22 V / 535 Ω, results in the initial current flowing through the circuit.
Here, the uncharged capacitor does not allow any current to pass initially, so the current is governed solely by the resistor and the emf of the battery. The current is determined by the total resistance in the circuit as the capacitor charges up gradually, allowing more current to flow through the circuit over time.