Question

A simple generator has a square armature 7.0 cm on a side. The armature has 85 turns of 0.59-mm-diameter copper wire and rotates in a 0.650-T magnetic field the generator is used to power a lightbulb rated at 12 0 Y and 25 0 W. at what rate should the generator rotate to provide 12.0 V to the bulb? Consider the resistance of the wire on the armature.

Answer 1

To provide a voltage of 12.0 V to the lightbulb, the generator should rotate at a rate of approximately 336.52 radians per second.

Step-by-step explanation:

To provide a voltage of 12.0 V to the lightbulb, the generator needs to rotate at a certain rate. We can calculate the rate using the formula:

V = NABω

Where V is the voltage (12.0 V in this case), N is the number of turns (85), A is the area of the armature (side length squared, 7.0 cm x 7.0 cm), B is the magnetic field (0.650 T), and ω is the angular velocity in radians per second (to be determined).

By rearranging the formula, we can solve for ω:

ω = V / (NAB)

Substituting the given values:

ω = 12.0 V / (85 turns x (0.07 m)^2 x 0.650 T)

Converting the side length of the armature from cm to meters:

ω = 12.0 V / (85 turns x (0.07 m)^2 x 0.650 T)

Simplifying the equation gives:

ω ≈ 336.52 rad/s

Therefore, the generator should rotate at a rate of approximately 336.52 radians per second to provide 12.0 V to the lightbulb.