Question

270 grams of copper pellets are removed from 250°C oven and immediately dropped into 750 mL of water in an insulated cup. The temperature of water raises 38°C then remains at that temperature. (Given, Sp. Heat of copper is 385 J/Kg°C).

Calculate the,

i) Heat energy removed from copper pellets in

Joules

Answer 1

The heat energy removed from the copper pellets is 3842.1 Joules.

Step-by-step explanation:

To calculate the heat energy removed from the copper pellets, we can use the formula:

Q = mcΔT

Where:

• Q is the heat energy
• m is the mass of the copper pellets (in kg)
• c is the specific heat capacity of copper (in J/kg°C)
• ΔT is the change in temperature (in °C)

Given:

• Mass of copper pellets = 270 grams = 0.27 kg
• Specific heat capacity of copper = 385 J/kg°C
• Change in temperature = 38°C

Plugging in these values into the formula:

Q = (0.27 kg)(385 J/kg°C)(38°C)

Q = 3842.1 Joules (rounded to 1 decimal place)