Question

A 24.30 V battery is used to supply current to a 29k R resistor. Assume the voltage drop across any wires used for connections is negligible. (a) What is the current (in MA ) through the resistor?

Answer 1

The current through a 29kΩ resistor connected to a 24.30V battery is calculated using Ohm's law (I = V/R), which results in a current of 0.839 mA.

Step-by-step explanation:

The student has asked how to calculate the current through a 29kΩ resistor when it is connected to a 24.30V battery. To find the current in milliamps (mA), one can use Ohm's law, which states that the current (I) through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor. In this case, I = V/R, where V = 24.30 volts and R = 29,000 ohms.

So, I = 24.30 V / 29,000 Ω = 0.000839 A. To convert this to milliamps, multiply by 1,000. Therefore, the current through the resistor is 0.839 mA.