Question

An AC circuit with the power supply 200 V at 120 hz (R=250 ohms, C=20 μF , L=150 mH). what is total capacitance for the circuit? please show all work, along with a phasor diagram.

Answer 1

The total capacitive reactance of the circuit is determined as 66.3 ohms.

The phasor diagram of the voltage and current is shown in the image attached.

How to calculate the total capacitance of the circuit?

The total capacitance of the circuit is calculated by applying the following formula as follows;

Xc = 1/ωC

Xc = 1/2πfC

where;

• C is the capacitance of the circuit
• f is the frequency of the AC circuit

Xc = 1 / ( 2π x 120 x 20 x 10⁻⁶)

Xc = 66.3 ohms

Thus, the total capacitive reactance of the circuit is determined as 66.3 ohms.

The phasor diagram is shown in the image attached.