Final answer:
To calculate the angular velocity of the tornado in revolutions per second, convert the given wind speed to m/s, find the radius from the given diameter, and apply the formula for angular velocity, ω = v/r. The final answer, after converting from radians to revolutions, is approximately 0.65 rev/s.
Step-by-step explanation:
The question involves the calculation of angular velocity of a tornado, given its diameter and the wind speed at its peak. To find the angular velocity in revolutions per second, we first need to convert the wind speed to meters per second, and then we can use the formula for angular velocity ω (omega), which is ω = v/r, where v is the linear velocity and r is the radius of the tornado.
First, convert the wind speed from km/h to m/s: 450 km/h = 450,000 m/3600 s = 125 m/s. Next, calculate the radius of the tornado, which is half of the diameter: r = 62.0 m / 2 = 31.0 m.
Now, compute the angular velocity: ω = 125 m/s / 31.0 m. However, this is in radians per second. To express it in revolutions per second, we divide by 2π (because there are 2π radians in one revolution): ω = (125/31.0) / 2π rev/s.
Carrying out the calculation, the angular velocity of the tornado is approximately 0.65 revolutions per second.