Final answer:
a. The final temperature is found by equating the heat gained by aluminum to the heat lost by gasoline, using the formula m⋅Δm⋅c⋅ΔT.
b. The total volume in the graduated cylinder after reaching thermal equilibrium is the sum of the initial volumes and the changes in volumes due to thermal expansion of aluminum and gasoline.
Step-by-step explanation:
This problem involves the principles of heat transfer, thermal equilibrium, and volume expansion. Let's break it down into two parts:
Part a: Finding the final temperature
The heat gained by aluminum equals the heat lost by gasoline. The heat gained or lost (Q ) can be calculated using the formula:
Q=mcΔT
where:
-m is the mass,
- c is the specific heat,
- ΔT is the change in temperature.
For aluminum:
Q Aluminum=mAluminum ⋅cAluminum ⋅ΔTAluminum
For gasoline:
QGasoline =mGasoline ⋅c Gasoline ⋅ΔTGasoline
Since no heat is transferred to the cylinder or the outside, the total heat gained by aluminum is equal to the total heat lost by gasoline:
mAluminum ⋅c Aluminum ⋅ΔT Aluminum =m Gasoline ⋅c Gasoline ⋅ΔTGasoline
Now, rearrange the equation and solve for the final temperature.
Part b: Finding the total volume
Once the aluminum and gasoline reach thermal equilibrium, they will have the same final temperature. Use the volume expansion coefficients to find the change in volume for each substance:
ΔVAluminum=VAluminum⋅βAluminum⋅ΔTfinal
ΔVGasoline =VGasoline ⋅β Gasoline ⋅ΔT final
The total volume in the graduated cylinder after reaching thermal equilibrium is the sum of the initial volumes and the changes in volumes:
Vtotal=VAluminum, initial +VGasoline, initial +ΔVAluminum +ΔV Gasoline
Now, substitute the given values and solve for the total volume.