Question

A circular wire loop of radius r=0.15 m and resistance R=8.2Ω rotates about a shaft through its diameter at a constant rate of f=5.45 Iz in a uniform B=0.39 - magnetic field directed perpendicular to the rotation axis. The plane of the loop is perpendicular to the magnetic field at time t= 0.

Answer 1

To calculate the emf induced in the circular wire loop, you can use the formula emf = BArω, where B is the magnetic field strength, A is the area of the loop, r is the radius of the loop, and ω is the angular frequency. Plug in the given values to calculate the emf.

Step-by-step explanation:

In this question, we have a circular wire loop of radius 0.15 m and resistance 8.2Ω rotating in a uniform magnetic field of 0.39 T. The loop rotates at a constant rate of 5.45 Iz around a shaft through its diameter. Since the plane of the loop is perpendicular to the magnetic field, an electromotive force (emf) will be induced in the loop. The emf can be calculated using the formula emf = BArω, where B is the magnetic field strength, A is the area of the loop, r is the radius of the loop, and ω is the angular frequency.

Given that the radius of the loop is 0.15 m, the magnetic field strength is 0.39 T, and the angular frequency is 5.45 Iz (convert to rad/s if needed), we can calculate the emf induced in the loop.

emf = BArω = (0.39 T)(π(0.15 m)^2)(5.45 Iz)

Find the product of these values to find the emf induced in the loop.