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What is the speed of a water wave that travels 27.97 meters in 4.71 seconds?

What is the period of a pendulum that has a length of 2.99 meters? Remember to use 10 m/s/s for "g".

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Final answer:

The speed of the water wave is 5.94 m/s. The period of the pendulum can be calculated using the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity.

Step-by-step explanation:

The speed of a water wave that travels 27.97 meters in 4.71 seconds can be calculated using the formula for wave speed (v), which is v = distance/time. By substituting the provided values into this formula, the wave speed can be found to be 27.97 meters / 4.71 seconds = 5.94 m/s.

To calculate the period of a pendulum (T) with a length (L) of 2.99 meters, using the approximation for acceleration due to gravity (g) of 10 m/s2, the formula T = 2π√(L/g) is used. Substituting the given values into this formula gives us T = 2π√(2.99/10), which can be solved to find the period of the pendulum.

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