Question

The drawing shows a wire composed of three segments AB, BC and CD.There is a current of I = 2.8 A in the wire. There is also amagnetic field B ( Magnetude = 0.26 T) that isthesame every where and the points in the direction of the + zaxis. The lengths of the wire segments areLAB = 1.1m,LBC = 0.55 m, andLCD = 0.55 m. Find the magnetude of the fircethat acts on each segment.

Answer 1

To find the magnitude of the force on each wire segment, use the equation F = I * B * L * sin(θ) with the given values of current, magnetic field, and wire segment length.

Step-by-step explanation:

To find the magnitude of the force that acts on each segment of the wire, we can use the equation F = I * B * L * sin(θ), where F is the force, I is the current, B is the magnetic field, L is the length of the wire segment, and θ is the angle between the current direction and the magnetic field direction.

For segment AB, the force is given by F = 2.8 A * 0.26 T * 1.1 m * sin(0°).

For segment BC and CD, the force is given by F = 2.8 A * 0.26 T * 0.55 m * sin(180°).