Final answer:
A 52 kg man standing on square stilts with each edge measuring 0.04 m applies a pressure of 159,250 Pa to the ground.
Step-by-step explanation:
To calculate the pressure applied to the ground by a 52 kg man standing on square stilts, we first need to find the force he exerts on the ground due to gravity (his weight), which is equal to his mass times the acceleration due to gravity (9.8 m/s²). The man's weight (W) is equal to 52 kg × 9.8 m/s², which gives us 509.6 N.
Next, we need to determine the area over which this force is distributed. The stilts have a square base with each edge measuring 0.04 m, therefore the area of one stilt (A) is 0.04 m × 0.04 m, which is 0.0016 m². Since the man stands on two stilts, the total area is twice that of one stilt, which is 0.0032 m².
Finally, using the formula for pressure (P) which is P = Force (F) / Area (A), the pressure exerted is 509.6 N / 0.0032 m², which equals to 159,250 Pa (pascals).