Question

As represented by the diagram, a wire coil with 33 turns and a radius of R=3.56 cm is coaxial with a solenoid that has a radius of r=1.23 cm and 575 turns uniformly distributed along its length of L=72,5 cm. The resistance of the coil is 2.01Ω. A The current in the solenoid varies sinusoidally at 60.0 Hz as Isol (t)=(17.9 A)sin(2π⋅60.0 Hz+t) What is the peak current, in milliamperes, through the coil? Ipeak = 1mA.

Answer 1

To find the peak current through the coil, calculate the magnetic field at the center of the coil caused by the changing current in the solenoid. Then, use the formula to calculate the peak current through the coil.

Step-by-step explanation:

To find the peak current through the coil, we need to calculate the magnetic field at the center of the coil caused by the changing current in the solenoid. The magnetic field at the center of the coil is given by:

B = μ0 × N × Isol / L

Where μ0 is the permeability of free space, N is the number of turns in the solenoid, Isol is the current in the solenoid, and L is the length of the solenoid.

Using the given values, we can calculate the magnetic field. Then, we can use the formula:

Ipeak = B × A × R / Rcoil

Where Ipeak is the peak current through the coil, B is the magnetic field at the center of the coil, A is the area of the coil, and Rcoil is the resistance of the coil.

Substituting the values and solving the equations will give us the peak current through the coil.