Question

Two blocks, m1=8.00 m 1 = 8.00 kg and m2=2.00 m 2 = 2.00 kg, are connected by a string that passes through a pulley, as diagrammed below. One block hangs freely, while the other block sits on a frictionless horizontal surface and is being pulled (or pushed) by a horizontal force F=Fxi^ F → = F x i ^ . In this problem we will consider the possibilities of the blocks moving in either direction. Assume that the acceleration due to gravity is 10ms^2. . What range of forces (provide magnitudes and directions) will allow mass m2 to accelerate upward? Explain your answer.

Answer 1

The range of forces is any force greater than 20 N, in the positive x-direction to allow mass m2 to accelerate upward, the force F must be greater than the force due to gravity on m2.

Step-by-step explanation:

In order for mass m2 to accelerate upward, the force F must be greater than the force due to gravity acting on m2. Considering that the acceleration due to gravity is 10 m/s^2, we can set up the following equation:

m2 * g < F

where m2 is the mass of the hanging block and g is the acceleration due to gravity. Plugging in the values, we get:

(2.00 kg) * (10 m/s^2) < F

20 N < F

Therefore, the range of forces that will allow mass m2 to accelerate upward is any force greater than 20 N, in the positive x-direction.