Question

A 12.0-V battery is connected in series with a cagaciton If the capscitance of the capacitor is 0.15μ, how much charge is on each of its plates?

Answer 1

The charge on each plate of the capacitor is 1.8 microcoulombs.

Step-by-step explanation:

The charge on each plate of a capacitor can be calculated using the formula Q = CV, where Q is the charge, C is the capacitance, and V is the applied voltage.

In this case, the capacitance of the capacitor is given as 0.15 μF (microfarads) and the voltage applied across it is 12.0 V. Plugging these values into the formula, we get:

Q = (0.15 µF) x (12.0 V) = 1.8 µC (microcoulombs)

Therefore, there is 1.8 microcoulombs of charge on each plate of the capacitor.