Final answer:
The axis of symmetry for the quadratic equation y = x² - 14x + 47 is x = 7.
Step-by-step explanation:
The equation of the axis of symmetry for a quadratic equation of the form ax² + bx + c = 0 can be found by using the formula x = -b / (2a). In the case of the quadratic equation y = x² - 14x + 47, the coefficients are a=1, b=-14, and c=47. Applying the formula, the axis of symmetry is x = -(-14) / (2*1) = 14 / 2 = 7. Therefore, the equation of the axis of symmetry is x = 7.