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Specify the center and radius of the circle x^(2)-4x+y^(2)-8y+11=0

User EGHDK
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1 Answer

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Final answer:

To find the center and radius of the circle, rewrite the equation in standard form (x-h)² + (y-k)² = r². Completing the square for x and y terms, the center is (2,4) and the radius is √15.

Step-by-step explanation:

To find the center and radius of the circle, we need to rewrite the equation in the standard form: (x-h)² + (y-k)² = r², where (h,k) represents the center of the circle and r represents the radius.

For the given equation:

x² - 4x + y² - 8y + 11 = 0

Completing the square for x terms, we get:

(x² - 4x + 4) + y² - 8y + 11 = 4 + 11

(x - 2)² + (y - 4)² = 15

Therefore, the center of the circle is (2,4) and the radius is √15.

User Durgpal Singh
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