Final answer:
To predict the offspring from the cross between a heterozygous, smooth pea pod plant and a wrinkled pea pod plant, we determine the genotypes of the parents, set up a Punnett square, and calculate the predicted genotypic and phenotypic ratios for the offspring. The parents are heterozygous smooth (Ss) and homozygous recessive wrinkled (ss). The predicted genotypic and phenotypic ratios for the offspring are both 1:1, meaning there is an equal chance of getting smooth (Ss) and wrinkled (ss) pea pods. None of the 50 seeds would be predicted to have a wrinkled pod.
Step-by-step explanation:
To predict the offspring from the cross between a heterozygous, smooth pea pod plant and a wrinkled pea pod plant, we need to determine the genotypes of the parents, set up a Punnett square with possible gametes, fill in the Punnett square for the resultant offspring, and calculate the predicted genotypic and phenotypic ratios for the offspring.
a. The genotype of the smooth pea pod parent is heterozygous (Ss), and the genotype of the wrinkled pea pod parent is homozygous recessive (ss).
b. The possible gametes for the heterozygous smooth pea pod parent are S and s, while the possible gametes for the wrinkled pea pod parent are s only.
c. The Punnett square for this cross will have two rows and two columns. The combinations of gametes will be Ss and ss.
d. The predicted genotypic ratio for the offspring will be 1:1, which means there is an equal chance of getting smooth (Ss) and wrinkled (ss) pea pods.
e. The predicted phenotypic ratio for the offspring will also be 1:1, meaning there is an equal chance of getting smooth (Ss) and wrinkled (ss) pea pods.
f. Since the wrinkled pea pod trait is recessive, all the offspring will have the genotype Ss, which means they will all have a smooth pea pod. Therefore, none of the 50 seeds would be predicted to have a wrinkled pod.