Final answer:
The area of each plate is approximately 33.9 x 10^-3 m².
Step-by-step explanation:
First, let's use the formula for the capacitance of a parallel-plate capacitor:
C = (ε₀ * A) / d
Where C is the capacitance, ε₀ is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of each plate, and d is the separation between the plates.
Given that C = 500 pF, ε₀ = 8.85 x 10^-12 F/m, and d = 0.6 mm = 0.6 x 10^-3 m, we can rearrange the formula to solve for A:
A = (C * d) / ε₀
Plugging in the values, we have:
A = (500 x 10^-12 F * 0.6 x 10^-3 m) / 8.85 x 10^-12 F/m
Calculating the above expression gives:
A ≈ 33.9 x 10^-3 m²
So, the area of each plate is approximately 33.9 x 10^-3 m².