Question

What is the capacitance of a capacitor with 20nC charge stored in 5V potential difference?

Answer 1

The capacitance of a capacitor with 20 nC charge and 5V potential difference is 4 nF.

Step-by-step explanation:

The student is asking about the capacitance of a capacitor given a certain charge and potential difference. The capacitance (C) can be found using the formula C = Q / V, where Q is the charge and V is the potential difference. In this case, the charge (Q) stored is 20 nC (nanocoulombs) and the potential difference (V) is 5V (volts).

The student's question can be solved as follows:

• Convert the charge from nanocoulombs to coulombs by multiplying by 10^-9: Q = 20 nC = 20 × 10^-9 C = 2 × 10^-8 C.
• Use the formula to calculate the capacitance: C = Q / V = (2 × 10^-8 C) / (5 V) = 4 × 10^-9 F.
• The capacitance of the capacitor is therefore 4 nF (nanofarads).