Question

fresnel coefficients. consider an emw perpendicular to the plane of incidence. the emw travels in air (n=1.000) and has an incident angle of 35 degrees on a transparent material of index of refraction 1.453. please calculate the reflected perpendicular fresnel coefficient and please provide your final result with four significant figures.

Answer 1

The reflected perpendicular Fresnel coefficient is approximately 0.009263.

Step-by-step explanation:

In order to calculate the reflected perpendicular Fresnel coefficient, we can use the Fresnel equations. The formula for the reflection coefficient (R) for light perpendicular to the plane of incidence is given by:

`\[ R = \left((n_1 - n_2)/(n_1 + n_2)\right)^2 \]`

where
`\( n_1 \)` is the refractive index of the first medium (air in this case, with
`\( n_1 = 1.000 \))` and
`\( n_2 \)` is the refractive index of the second medium (the transparent material with
`\( n_2 = 1.453 \))`. The incident angle
`(\( \theta_i \))` is 35 degrees.

Substituting the given values into the formula, we get:

`\[ R = \left((1.000 - 1.453)/(1.000 + 1.453)\right)^2 \]`

Solving this expression yields the reflected perpendicular Fresnel coefficient
`(\( R \))`, and rounding it to four significant figures, we find
`\( R \approx 0.009263 \)`.

Therefore, the final answer is that the reflected perpendicular Fresnel coefficient is approximately 0.009263.