Question

A 1000-turn ideal solenoid has a length of 10cm.The inductance of the solenoid is 4.0x10³ H. To generate an emf of 2.0 V, the current should change at a rate of: (hint: you may not need to use all the numbers provided to determine the answer.)

A. 2.0x10⁻³ A/s
B. 2.0x10² A/s
C. 5 A/s
D 50 A/s
E./500 A/s

Answer 1

The rate of change of current necessary to generate an emf of 2.0 V in a 1000-turn ideal solenoid with an inductance of 4.0 x 10^3 H is 5 x 10^-4 A/s.

Step-by-step explanation:

The rate of change of current necessary to generate an electromotive force (emf) of 2.0 V in a 1000-turn ideal solenoid can be determined using the formula:

Emf = -L*(dI/dt)

Where Emf is the induced emf, L is the inductance of the solenoid, and (dI/dt) is the rate of change of current. Rearranging the formula to solve for (dI/dt), we have:

(dI/dt) = -Emf/L

Substituting the given values, (dI/dt) = -2.0 V / (4.0 x 10^3 H) = -5.0 x 10^-4 A/s. Since the rate of change of current cannot be negative, the answer is 5 x 10^-4 A/s.