Final answer:
The ratio of the kinetic energy of the truck to that of the astronaut is approximately 0.0024, which means the truck's kinetic energy is about 0.24% of the astronaut's.
Step-by-step explanation:
To calculate the ratio of the kinetic energy of the truck to that of the astronaut, we use the kinetic energy formula:
KE = ½ mv², where m is the mass of the object and v is the velocity.
For the truck:
Mass (m) = 19500 kgVelocity (v) = 95 km/h = 95,000 m/3600 s = 26.39 m/s
KEtruck = ½ × 19500 kg × (26.39 m/s)²
For the astronaut:
Mass (m) = 92.5 kgVelocity (v) = 28000 km/h = 28000,000 m/3600 s = 7777.78 m/s
KEastronaut = ½ × 92.5 kg × (7777.78 m/s)²
Now, we calculate each one:
KEtruck = ½ × 19500 × (26.39)² = 6.75 × 106 J (Joules)KEastronaut = ½ × 92.5 × (7777.78)² ≈ 2.8 × 109 J
The ratio of the kinetic energies is then:
KEtruck / KEastronaut = (6.75 × 106 J) / (2.8 × 109 J) = 0.0024
Therefore, the kinetic energy of the truck is approximately 0.24% of that of the astronaut.