Final answer:
The magnitude of the magnetic field experienced by an electron moving in the y-direction and experiencing a force in the z-direction is calculated to be 0.04 Tesla, based on the known force and velocity of the electron.
Step-by-step explanation:
The question pertains to the principles of magnetic force on a moving charged particle, specifically an electron. According to the Lorentz force law, the magnetic force (F) experienced by a moving charge (q) in a magnetic field (B) is given by F = qvBsin(θ), where v is the velocity of the charge, B is the magnetic field, and θ is the angle between the velocity vector and the magnetic field vector. Since the electron experiences a force only when traveling in the positive y direction and not the positive x direction, we can deduce that the magnetic field must be in the z direction. Given the force of 3.5×10⁻¹³ N, the speed of the electron (5.5×10⁵ m/s), and the elementary charge (q = -1.60×10⁻¹¹ C), and assuming that the angle θ between the velocity and magnetic field is 90 degrees (since it's the condition where the force reaches its maximum), we can calculate the magnitude of the magnetic field (B) as:
B = F / (|q|v) = 3.5×10⁻¹³ N / (1.60×10⁻¹¹ C × 5.5×10⁵ m/s) = 0.04 T
So, the magnitude of the magnetic field is 0.04 Tesla.