Question

A rigid tank initially contains 27lbm of air at 84∘ F and 20.6 psia. Additional air is added to the tank and now the temperature is 96.6 ∘ F and the pressure is now 38.11 psia. a) What is the volume of the tank

Answer 1

The volume of the tank is approximately 26.867 L.

Step-by-step explanation:

To find the volume of the tank, we can use the ideal gas law equation:

P1 * V1 / T1 = P2 * V2 / T2

We are given the following information:

P1 = 20.6 psi

V1 = ?

T1 = 84°F = 84 + 459.67 = 543.67K

P2 = 38.11 psi

V2 = ?

T2 = 96.6°F = 96.6 + 459.67 = 556.27K

Plugging in these values, we can solve for V2:

20.6 * V1 / 543.67 = 38.11 * V2 / 556.27

Cross-multiplying and rearranging the equation:

V1 = (38.11 * V2 * 543.67) / (20.6 * 556.27)

Calculating the value, we find that the volume of the tank is V1 = 26.867 L.