Question

Juliet's pass code has a combination which is divisible by 11. If you get the sum of its digits, the result is 6. What is the number combination of Juliet's pass code?

Answer 1

One possible combination for Juliet's passcode that sums up to 6 and is divisible by 11 is either 42 or 51.

Step-by-step explanation:

The subject of this question is finding a number combination with two specific properties: firstly, the combination is divisible by 11, and secondly, the sum of its digits equals 6.

To approach this, we should recall a rule for divisibility by 11: a number is divisible by 11 if the difference between the sum of the digits in odd positions and the sum of the digits in even positions is either 0 or a multiple of 11.

As we search for a number whose digits add up to 6, the following options appear possible: 15 (1+5=6), 24 (2+4=6), 42 (4+2=6), and 51 (5+1=6). Of these possibilities, 42 and 51 are multiples of 11 that also fit the criteria of their digits summing up to 6.