Question

In one trial, the radius of the drops is observed to be 6.95×10⁻⁷ m . The density of the oil is 824.0 kg/m3 . What is the mass of the drops in this trial?

Answer 1

To determine the mass of oil drops in the experiment with a radius of 6.95×10⁻⁷ m and density of 824.0 kg/m³, calculate the sphere's volume and multiply by the density.

Step-by-step explanation:

To calculate the mass of the oil drops in a Millikan's oil-drop experiment, with a given radius of 6.95×10⁻⁷ m and a density of 824.0 kg/m³, we use the formula for the volume of a sphere – V = ⅔πr³ – and the definition of density – ρ = mass/volume. First, we calculate the volume: V = ⅔π(6.95×10⁻⁷ m)³. Then, we multiply the volume by the density to get the mass: mass = ρ ⋅ V.

For this specific trial the calculation would be:

1. Volume, V = ⅔π(6.95×10⁻⁷ m)³
2. Mass, mass = 824.0 kg/m³ ⋅ V

After calculating V you would multiply it by the given density to find the oil drop's mass in kilograms.