Question

A gold coin (33.5 g) is dropped from the top of the Burj Dubai building, 630 m above ground level. In the absence of air resistance, how fast would it be moving when it hit the ground?

Answer 1

Ignoring air resistance, the final velocity of a gold coin dropped from 630 meters high would be approximately 111.19 meters per second when it hits the ground, calculated using the kinematic equation for freely falling objects.

Step-by-step explanation:

The subject of the question is Physics, specifically it is related to classical mechanics, dealing with the motion of objects under the influence of gravity. The student is inquiring about the final velocity of a gold coin as it hits the ground after being dropped from a significant height, the Burj Dubai, which is 630 meters tall.

Ignoring air resistance, we can use the following kinematic equation for freely falling objects to solve for the final velocity (v) of the coin:

v = √(2gh)

where:

• g is the acceleration due to gravity, which is approximately 9.81 m/s²
• h is the height from which the coin is dropped, which is 630 m

Plugging in the values, we get:

v = √(2 * 9.81 m/s² * 630 m)
v = √(12362.7 m²/s²)
v ≈ 111.19 m/s

Therefore, if air resistance is neglected, the gold coin would be moving at approximately 111.19 meters per second when it hits the ground after being dropped from the top of the Burj Dubai building.