Final answer:
Calculating the heat contained in 100 kg of water at 60 degrees Celsius using the specific heat capacity gives a result of 25,116,000 joules, which doesn't match any of the provided options, suggesting an error in the question or the provided answer choices.
Step-by-step explanation:
The amount of heat contained in 100 kg of water at 60 degrees Celsius can be calculated using the specific heat capacity formula: Q = mCΔT, where Q is the heat energy in joules, m is the mass in kilograms, C is the specific heat capacity (for water this is approximately 4,186 J/kg°C), and ΔT is the change in temperature in degrees Celsius. Given that the specific heat capacity of water is 4,186 J/kg°C, the mass m is 100 kg, and the temperature change for this scenario is not provided because we are dealing with the absolute amount of heat, not a change, we can still use the specific heat capacity as a reference to estimate the amount of heat.
Therefore, the heat contained in the water is Q = mCΔT = 100 kg × 4,186 J/kg°C × 60°C. This equals Q = 25,116,000 J, which is not one of the options provided. It appears there might be an error in the options or the question itself because none of the answer choices match the correct calculation. If this calculation seems excessive, it's because we are asked for the total heat content at a certain temperature, not just the amount needed to increase its temperature. However, if the question were asking how much heat it would take to increase the temperature of 100 kg of water by 60°C, then the answer would be 25,116,000 J which would be most closely approximated by option D (4,180,000 Joules), but still, it's not a precise match.