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At tt = 1.0 ss, a 0.65 kgkg object is falling with a speed of 6.5 m/sm/s. At tt = 2.0 ss, it has a kinetic energy of 38 JJ.

What is the kinetic energy of the object at tt = 1.0 ss?

User Everth
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Final answer:

The kinetic energy of the 0.65 kg object falling with a speed of 6.5 m/s at t = 1.0 s is calculated using the formula KE = ½mv² and is found to be approximately 13.73 J.

Step-by-step explanation:

To find the kinetic energy of the object at t = 1.0 s, we can use the formula for kinetic energy, KE = ½mv², where m is the mass of the object and v is its velocity at that time. Given that the mass of the object is 0.65 kg and the velocity at t = 1.0 s is 6.5 m/s, we can calculate the kinetic energy at that time.

Plugging the values into the equation:

KE = ½(0.65 kg)(6.5 m/s)²

KE = ½(0.65 kg)(42.25 m²/s²)

KE = ½(27.4625 kg · m²/s²)

KE = 13.73125 J

Therefore, the kinetic energy of the object at t = 1.0 s is approximately 13.73 J.

User Kgalic
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