Final answer:
The kinetic energy of the 0.65 kg object falling with a speed of 6.5 m/s at t = 1.0 s is calculated using the formula KE = ½mv² and is found to be approximately 13.73 J.
Step-by-step explanation:
To find the kinetic energy of the object at t = 1.0 s, we can use the formula for kinetic energy, KE = ½mv², where m is the mass of the object and v is its velocity at that time. Given that the mass of the object is 0.65 kg and the velocity at t = 1.0 s is 6.5 m/s, we can calculate the kinetic energy at that time.
Plugging the values into the equation:
KE = ½(0.65 kg)(6.5 m/s)²
KE = ½(0.65 kg)(42.25 m²/s²)
KE = ½(27.4625 kg · m²/s²)
KE = 13.73125 J
Therefore, the kinetic energy of the object at t = 1.0 s is approximately 13.73 J.