Question

A neon sign transformer has a 510 W AC output with an rms voltage of 13kV when connected to a normal household outlet. There are 500 turns of How many tums of wire does the socondary coil have? wire in the primary coil.

Answer 1

To determine the number of turns in the secondary coil of a step-up transformer, the formula for a transformer's turn ratio, which is based on Faraday's law of electromagnetic induction, can be used. With the primary voltage assumed at 120 V and given values of 13,000 V for the secondary voltage and 500 turns for the primary coil, the calculation yields 54,165 turns in the secondary coil.

Step-by-step explanation:

The subject of the question is transformers, which is a topic in Physics. Specifically, the question involves determining the number of turns in the secondary coil of a step-up transformer given the power, voltage output, and number of turns in the primary coil. The transformer's primary coil is connected to a household outlet and has 500 turns, with an output of 13kV at 510W of AC power.

To find the number of turns in the secondary coil, we use the formula for a transformer's turn ratio, which is derived from Faraday's law of electromagnetic induction:

• Vp / Vs = Np / Ns

where Vp is the primary voltage, Vs is the secondary voltage, Np is the number of primary turns, and Ns is the number of secondary turns.

In this case, we are given Vs = 13,000 V and Np = 500 turns. Assuming the household outlet voltage (Vp) is 120 V (typical in the United States), the number of turns in the secondary coil (Ns) can be calculated as follows:

Ns / Np = Vs / Vp

Ns = (Vs / Vp) × Np

Ns = (13,000 V / 120 V) × 500 turns

Ns = (108.33) × 500 turns

Ns = 54,165 turns