Final answer:
The maximum magnetic field strength in the electromagnetic wave created by a normal heart beating, which creates a 4.00-mV potential across 0.300 m of chest, is approximately 4.43 × 10^-11 T. The maximum electric field strength created is 0.0133 V/m, and the wavelength of the resulting wave is 3 × 10^8 m.
Step-by-step explanation:
The magnetic field strength in the wave created by a heartbeat can be calculated if we know the maximum electric field strength. Based on the provided information, during normal beating, the heart creates a maximum 4.00-mV potential across 0.300 m of a person's chest, creating a 1.00-Hz electromagnetic wave. The relationship between the electric field (E) and magnetic field (B) in an electromagnetic wave is given by the equation c = E / B, where c is the speed of light in a vacuum (approximately 3 × 108 m/s).
To find the maximum electric field strength, we use the equation E = V/d, where V is the potential difference and d is the distance. For a potential difference of 4.00 mV (0.004 V) across 0.300 m, E = 0.004 V / 0.300 m = 0.0133 V/m. To find the corresponding maximum magnetic field strength, we rearrange c = E / B to get B = E / c, resulting in B = 0.0133 V/m / (3 × 108 m/s) = 4.43 × 10-11 T (tesla).
The wavelength of the electromagnetic wave can be calculated using the equation λ = c / f, where λ is the wavelength and f is the frequency. For a frequency of 1.00 Hz, the wavelength λ = 3 × 108 m/s / 1.00 Hz = 3 × 108 m.