Question

An electron in the cathode ray tube of a television set enters a region where it accelerates uniformly from a speed of 55700 m/s to a speed of 4.12×10⁶ m/s in a distance of 2.9 cm. What is its acceleration?

Answer 1

The acceleration of the electron is 1.37x10^8 m/s^2.

Step-by-step explanation:

The acceleration of an electron can be calculated using the formula:

a = (vf - vi) / d

where a is the acceleration, vf is the final velocity, vi is the initial velocity, and d is the distance traveled.

Plugging in the given values, we have:

a = (4.12x10^6 m/s - 5.57x10^4 m/s) / 2.9x10^-2 m = 1.37x10^8 m/s^2

Therefore, the acceleration of the electron is 1.37x10^8 m/s^2.