Question

Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ×10⁶ V/m ). The plates are separated by 2.88 mm and a potential difference of 5505 V is applied.

Answer 1

The electric field strength between the two parallel conducting plates will not exceed the breakdown strength for air.

Step-by-step explanation:

The electric field strength between two parallel conducting plates can be determined using the formula:

E = V/d where E is the electric field strength, V is the potential difference, and d is the distance between the plates.

For the given problem, the plates are separated by 2.88 mm and a potential difference of 5505 V is applied. Plugging these values into the formula, we get:

E = 5505 V / 2.88 mm = 1910 V/m

Since the calculated electric field strength (1910 V/m) is lower than the breakdown strength for air (3 ×10⁶ V/m), it will not exceed the breakdown strength.