Question

A soccer player runs up behind a soceer ball (of mass 0.50 kg ) that is moving at 3.5 m/s ) the same direction as the player. The soccer player kicks it and the ball moves with a speed of 13.5 m/s. What is the magnitude of the impulse (in kgm/s ) delivered to the soccer ball?

a. 5.0
b. 7.5
c. 10,0
d. 15.0

Answer 1

The magnitude of the impulse delivered to the soccer ball is calculated using the change in momentum, resulting in 5.0 kgm/s as the correct answer.

Step-by-step explanation:

The magnitude of the impulse delivered to the soccer ball can be calculated using the change in momentum, which is the mass times the change in velocity. The formula for impulse (J) is:

J = Δp = m(v_f - v_i)

Where:

• m is the mass of the object,
• v_f is the final velocity,
• v_i is the initial velocity.

Given that the mass of the soccer ball is 0.50 kg, the initial velocity is 3.5 m/s, and the final velocity after the kick is 13.5 m/s, the impulse would be:

J = 0.50 kg * (13.5 m/s - 3.5 m/s) = 0.50 kg * 10 m/s = 5.0 kgm/s

Therefore, the correct answer is (a) 5.0 kgm/s.