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Fill in the blank with the correct answer. Sami suggested replacing the copper wire used in the socket with an aluminum wire. He first wants to find the drift speed of the electrons inside the aluminum wire. The wire is connected to a socket where the current flows through it has a magnitude of 12 A. The wire has a radius of 4.0 mm and a density of 2.7 g/cm³ . The drift speed of an electron inside the aluminum wire is ____n/s if each atom is given only one conduction electron. The molar mass of the aluminum is 27 g/mol. Avogadro's number is equal to 6.0×10²³ mol⁻¹

User Adam Rice
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Final answer:

The drift speed of an electron inside the aluminum wire, given the provided parameters and assuming one conduction electron per atom, is calculated to be 396,000 n/s.

Step-by-step explanation:

Calculating the Drift Speed of Electrons in an Aluminum Wire

To calculate the drift speed of electrons in an aluminum wire carrying a current of 12 A, with a wire radius of 4.0 mm (0.004 m), and aluminum density of 2.7 g/cm³ (2.7 x 10³ kg/m³), and a molar mass of aluminum of 27 g/mol, we use the equation I = nqAvd, where I is the current, n is the number of free electrons per volume, q is the charge of an electron (-1.60 x 10⁻¹⁹ C), A is the cross-sectional area of the wire, and vd is the drift speed of the electrons.

First, convert density of aluminum to kg/m³:
2.7 g/cm³ = 2700 kg/m³.

Next, find the number of moles in 1 kg of aluminum:
1 kg / 27 g/mol = 1 kg / 0.027 kg/mol = 37.04 mol.

Now, find the number of free electrons in 1 kg of aluminum by using Avogadro's number:
37.04 mol x 6.0×10²³ mol⁻¹ = 2.22×10²¸ free electrons.

Then, calculate the number of electrons per cubic meter. Since density is 2700 kg/m³, there are:
2700 kg/m³ x 2.22×10²¸ electrons/kg = 5.99×10²¹ electrons/m³.

The wire's cross-sectional area, A, is πr², where r is radius. So, A = π(0.004 m)² = 5.03×10⁻µ m².

Now, use these values in the drift speed formula:
12 A = (5.99×10²¹ electrons/m³)(-1.60 x 10⁻¹⁹ C/electron)(5.03×10⁻µ m²)vd.

Solving for vd gives us:
vd = 12 A / [(5.99×10²¹ electrons/m³)(-1.60 x 10⁻¹⁹ C/electron)(5.03×10⁻µ m²)]
vd = 0.396 m/s or 396000 n/s.

The drift speed of an electron inside the aluminum wire is 396,000 n/s.

User Judi
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