Question

protons with momentum 5.1*10⁻²¹ kg.m/s are magnetically steered in a horizontal circular path 2.8 m in diameter.In the top view of the path the protons move clockwise. determine the magnitude of the field in the magnets surrounding the beam pipe.

Answer 1

The magnitude of the field in the magnets surrounding the beam pipe can be determined by using the formula for the magnetic field in a circular path. The magnetic field strength is approximately 2.678 x 10^-2 T.

Step-by-step explanation:

To determine the magnitude of the field in the magnets surrounding the beam pipe, we can use the formula for the magnetic field in a circular path.

The formula is given as:

B = (mv) / (qR)

Where B is the magnetic field, m is the mass of the proton, v is the velocity of the proton, q is the charge of the proton, and R is the radius of the circular path.

In this case, the momentum of the proton is given as 5.1 x 10^-21 kg.m/s and the diameter of the circular path is given as 2.8 m. We can use these values to calculate the radius of the circular path by dividing the diameter by 2, which gives us a radius of 1.4 m.

Now we can substitute the values into the formula to find the magnetic field:

B = (5.1 x 10^-21 kg.m/s) / ((1.6 x 10^-19 C)(1.4 m))

Calculating this expression gives us the magnetic field of approximately 2.678 x 10^-2 T (or Tesla).