Final answer:
The total resistance of a circuit with a 6.0Ω and a 2.0Ω resistor in series connected to a 12 V battery is 8.0Ω, and the current through the circuit is 1.5 A, calculated using Ohm's law.
Step-by-step explanation:
The question involves calculating the total resistance and current in a circuit with a 12 V battery and two resistors in series. To find the total resistance, we add the resistance values of the individual resistors. In this case, a 6.0Ω and a 2.0Ω resistor in series have a total resistance of 8.0Ω (6.0Ω + 2.0Ω). To calculate the current flowing through the circuit, we use Ohm's law, which states that current (I) equals voltage (V) divided by resistance (R). Therefore, the current in the circuit is I = V/R = 12 V / 8.0Ω, which equals 1.5 A.