Question

A flywheel with a radius of 0.360 m starts from rest and accelerates with a constant angular acceleration of 0.790rad/s² Compule the magnitude of the tangential acceleration, the radial acceleration, and the resultant acceleration of a point on its rim after it has turned through 60.0.

Answer 1

The magnitude of the tangential acceleration is 0.2844 m/s², the magnitude of the radial acceleration is 0.600 m/s², and the magnitude of the resultant acceleration is 0.646 m/s².

Step-by-step explanation:

To find the magnitude of the tangential acceleration, we can use the formula:

at = r * α

where r is the radius and α is the angular acceleration. Plugging in the values, we get:

at = 0.360 * 0.790 = 0.2844 m/s²

To find the magnitude of the radial acceleration, we can use the formula:

ar = r * ω²

where r is the radius and ω is the angular velocity. Plugging in the values, we get:

ar = 0.360 * (100/60)² = 0.600 m/s²

To find the magnitude of the resultant acceleration, we can use the Pythagorean theorem:

a = sqrt(at² + ar²)

Plugging in the values, we get:

a = sqrt((0.2844)² + (0.600)²) = 0.646 m/s²