Final answer:
The magnetic field inside a solenoid is calculated using the formula B = μ_0 * (n * I), where μ_0 is the permeability of free space, n is the number of turns per unit length, and I is the current. The magnetic field in a 25.0 cm long solenoid with 400 turns and 80.0 A current is 1.60 x 10^-2 T.
Step-by-step explanation:
To calculate the magnetic field inside a solenoid, we use Ampère's Law which simplifies to the formula:
B = μ_0 * (n * I)
Where B is the magnetic field, μ_0 is the permeability of free space (μ_0 = 4π x 10^-7 T*m/A), n is the number of turns per unit length of the solenoid, and I is the current passing through the coils.
The number of turns per unit length n is calculated as the total number of turns divided by the length of the solenoid:
n = Total turns / Length
For a solenoid that is 25.0 cm long with 400 turns and current of 80.0 A, the magnetic field can be calculated as follows:
n = 400 turns / 0.25 m = 1600 turns/m
Then, plug into the formula to find B:
B = (4π x 10^-7 T*m/A) * (1600 turns/m * 80.0 A)
B = 1.60 x 10^-2 T
Therefore, the magnetic field in the solenoid is 1.60 x 10^-2 T (Tesla).