Question

In a particular situation, involving an object in front of a lens with a focal length of +18.0 cm, the magnification is +5.00 .

(a) Determine the object distance.
(b) Determine the image distance.

Answer 1

The object distance is 72.0 cm and the image distance is -14.4 cm.

Step-by-step explanation:

The object distance can be determined using the lens formula:

1/f = 1/do + 1/di

where f is the focal length, do is the object distance, and di is the image distance.

In this case, the focal length is +18.0 cm and the magnification (m) is +5.00. The magnification can be calculated using the formula:

m = -di/do

Solving these equations simultaneously, we can find the object and image distances:

5.00 = -di/do

1/18.0 cm = 1/do + 1/di

Solving these equations, we find that the object distance (do) is 72.0 cm and the image distance (di) is -14.4 cm.