Question

The hammer throw is a track and field event in which 7.30 kg ball (the hammer) is whirled around in a circle several times and released. it then moves upward on the familiar curved path of projectile motion and eventually returns to the ground some distance away. The word record for tbe horizontaldistance is 86,75 m, achieved in 1986 by Vuriy Sedylh. Ignore air resistance and the fact that the ball was released above the ground rather than at ground level. Furthermore, assume that the ball is whirled around a circle that has a redius of 2.28 mand that its velocity at the instant of release is directed 51.3 ∘ above the horizontal. Find the magnitude of the centripetal force acting on the ball just peior to the moment of release. Number Units

Answer 1

The student's question on finding the centripetal force in a hammer throw event cannot be completely answered without additional information such as the velocity of the hammer at the moment of release.

Step-by-step explanation:

The student is asking for the calculation of the centripetal force acting on a hammer during the hammer throw event in track and field. To find the centripetal force, we must use the following formula:

Fc = m * (v2 / r)

where:

• m is the mass of the hammer,
• v is the linear velocity of the hammer at the moment of release,
• r is the radius of the circular path.

The velocity (v) can be inferred from the world record throw's parameters, but since it's not provided directly in the question, this step will involve using projectile motion equations to find velocity. However, without the angle of release or the time the hammer was in the air, we cannot solve this question completely. Overall, the question cannot be answered as critical information is missing.