Question

A capacitor attached to a 29.8 V battery acquires a charge of 7C over a period of 3 seconds. How much energy is required to charg the capacitor?

Select the correct answer
a. 231 J
b. 112 J
c. 313J
d. 401 J
e. 255 J

Answer 1

The amount of energy required to charge the capacitor is approximately 102.692 J.

Step-by-step explanation:

To calculate the energy stored in a capacitor, we can use the formula:

Energy (E) = 0.5 * C * V^2

Where C is the capacitance and V is the voltage across the capacitor.

In this case, the capacitance is not given. However, we can calculate it using the formula:

C = Q / V

Where Q is the charge on the capacitor and V is the voltage across the capacitor.

Given that the charge on the capacitor is 7C and the voltage across the capacitor is 29.8V, we can calculate the capacitance:

C = 7C / 29.8V = 0.235 F

Now we can calculate the energy:

E = 0.5 * 0.235 F * (29.8 V)^2 = 102.692 J

Therefore, the amount of energy required to charge the capacitor is approximately 102.692 J.